Question

Arun borrowed a sum of money from Jayant at the rate of 8% per annum simple interest for
the first four years, 10% per annum for the next 6 years and 12% per annum for the period
beyond 10 yerras. If he pays a total of Rs. 12,160 as interest only at the end of 15 years,
how much money did he borrow?
(A) Rs. 12,000 (B) Rs. 10,000 (C) Rs. 8,000 (D) Rs. 9,000

Answer 1

Answer : (C) Rs. 8,000 __________________________SOLUTION :_____________________In the first case : Given that : Arun borrowed a sum of money from Jayant at the rate of 8% per annum simple Interest for first for years. Let, the Principal be P As we know that : $S.I. = \frac{P \times r \times t}{100} \\ \\ = &gt; S.I. = \frac{P \times 8 \times 4}{100} ....(1)$In the second case : Given that : Arun borrowed 10% per annum for the next 6 years. Again, $S.I. = \frac{P \times r \times t}{100} \\ \\</p><p>= > S.I. = \frac{P \times 10 \times6 }{100} ....(2)$In the third case : Given that : At last Arun borrowed 12% per annum for the period beyond 10 years.But also given that : he pays the interest of 15 years. Then total years = 4+6+10 = 20 But he pays the interest of 15 years that's why the remaining years = 20-15 = 5 years.Then in third case the time will be 5 years.

$S.I. \: = \frac{P \times r \times t}{100} \\ \\ = > S.I. = \frac{P \times 12 \times5}{100} ...(3)$Arun pays Rs. 12,160 at the end of 15 years

$S.I. \: = \frac{P \times r \times t}{100} \\ \\ = > S.I. = \frac{P \times 12 \times5}{100} ...(3)$Arun pays Rs. 12,160 at the end of 15 years.Now, According to the question : $\frac{P \times 8 \times 4}{100} + \frac{P \times10 \times 6 }{100} + \frac{P \times 12 \times 5}{100} = 12160 \\ \\ = > 32P + 60P + 60 P =1 2160 \times 100 \\ \\ = > 152P = 12160 \times 100 \\ \\ = > P = \frac{12160 \times 100}{152} \\ \\ = > P = 8000$So, Arun borrowed Rs. 8000

Answer 2

Answer:

c 8000

Step-by-step explanation:

c the pic

answer is there