Math, asked by niharika12345, 1 year ago

Arun bought a car for ₹ 3,50,000. The next year, the price went upto ₹3,70,000. What was the Percentage of the price increase?

Answers

Answered by pratyush4211
68
Arun Bought Car for=₹3,50,000
Next Year Price=₹3,70,000

Increase=370000-350000
=₹20000

Increase\% = \frac{increase}{original \: price} \times 100 \\ = \frac{20000}{350000} \times 100 \\ = 5.71\%
Increase=5.71%
Answered by Pinkblossom
18

Answer:

ᴡᴇ ʜᴀᴠᴇ ,

ɪɴᴛɪᴀʟ ᴘʀɪᴄᴇ = ₹3,50,000

ꜰɪɴᴀʟ ( ɪɴᴄʀᴇᴀꜱᴇᴅ ) ᴘʀɪᴄᴇ = ₹3,70,000

ɪɴᴄʀᴇᴀꜱᴇᴅ ᴀᴍᴏᴜɴᴛ = ₹( 3,70,000-3,50,00)= 20,00

⇒ᴘᴇʀᴄᴇɴᴛᴀɢᴇ ɪɴᴄʀᴇᴀꜱᴇ = ɪɴᴄʀᴇᴀꜱᴇᴅ ᴀᴍᴏᴜɴᴛ / ɪɴɪᴛɪᴀʟ ᴀᴍᴏᴜɴᴛ × 100

⇒ ᴘᴇʀᴄᴇɴᴛᴀɢᴇ ɪɴᴄʀᴇᴀꜱᴇ = 20,000 / 3,50,000 × 100 = 200/35 = 40/ 7 = 5ᴡʜᴏʟᴇ 5/7 % [ᴀɴꜱ]

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