Arun is 4.5 M long and 4 metre wide the floor of the room is to be covered with tiles of Size 15 CM by 10 cm find the cost of covering the floor with tiles at the rate of ₹ 4.50 per tile
Answers
Answered by
41
Arun = a room (i hope so)
The area of the room = 18m^2 = 180000cm^2
The area of a tile = 150 cm^2
Number of tiles required is 180000/150 = 1200
Cost of 1 tile = ₹ 4.50
Cost of 1200 tiles = ₹ 5400
The floor can be covered in ₹ 5400
The area of the room = 18m^2 = 180000cm^2
The area of a tile = 150 cm^2
Number of tiles required is 180000/150 = 1200
Cost of 1 tile = ₹ 4.50
Cost of 1200 tiles = ₹ 5400
The floor can be covered in ₹ 5400
arinjayjain24:
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Answered by
11
Area of room =450*400=180000cmsq
Tile area =15*10=150cm
So total tiles req=180000/150=1200
Cost of total tiles=1200*4.5=5400 rs
Tile area =15*10=150cm
So total tiles req=180000/150=1200
Cost of total tiles=1200*4.5=5400 rs
it is correct answer
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