Question

arun is now half as old as his father.12 years ago father's age was 3 times as old as Arun.Find their present age.​

Answer 1

Step-by-step explanation:

let father age=f

arun age=f/2

12 years ago

father=f-12

arun=(f/2)-12

as per given condition,

f-12=3{(f/2)-12}

f-12=(3f/2)-36

f-3f/2=-36+12

(2f-3f)/2=-24

-f/2=-24

(minus sign cancels from both sides)

f/2=24

f=24×2

f=48

present age of father = 48 yrs

present age of arun = half of 48 = 24 yrs

hope it helps

plzzz mark as brainliest

Answer 2

$\bf{\huge{\underline{\boxed{\sf{\red{Answer:}}}}}}$

$\bf{\underline{\sf{\blue{Given:}}}}$

• Arun is now half as old as his Father
• 12 years ago father's age was 3 times as old as Arun.

$\bf{\underline{\sf{\blue{To\:find:}}}}$

• Present age of Arun
• Present age of Father

$\bf{\underline{\sf{\blue{Solution:}}}}$

Let the present age of Arun be x years

Let the present age of Father be y years

$\bf{\underline{\sf{\green{As\:per\:first\:condition:}}}}$

$\bf\sf{x}$ = $\bf\sf\frac{1}{2}$ y

$\bf\sf{x}$ = $\bf\sf\frac{y}{2}$ ---> 1

$\bf{\underline{\sf{\green{As\:per\:second\:condition:}}}}$

• 12 years ago father's age was 3 times as old as Arun.

Ages 12 years ago :-

Arun's age = x - 12 years

Father's age = y - 12 years

Representing it mathematically,

=> (y - 12) = 3 ( x - 12)

=> y - 12 = 3x - 36

=> 3x - 36 = y - 12

=> 3x - y = - 12 + 36

=> 3x - y = 24 -----> 2

Substitute value of x from equation 1 in equation 2,

=> 3 × $\sf\frac{y}{2}$ - y = 24

=> $\sf\frac{3y}{2}$ - y = 24

=> $\sf\frac{3y-2y}{2}$ = 24

=> 3y - 2y = 24 × 2

=> 3y - 2y = 48

=> y = 48

Substitute value of y in equation 2,

3x - y = 24 ---> 2

3x - 48 = 24

3x = 24 + 48

3x = 72

x = $\sf\frac{72}{3}$

x = 24

•°• Present age of Arun = x = 24 years

Present age of Father = y = 48 years.