Question

arun is twice as old as seema.five years ago his age was three times seema's age. find there present ages.

Answer 1

Let Seema 's age be x and Arun age be 2x

5 YEARS HENCE
Seema age = x-5
Arun age= 2x-5
Now,
2x-5=3 (x-5)
2x-5=3x- 15
2x-3x=-15+5
-x=-10
x=10
SEEMA AGE = 10YEARS
ARUN AGE= 20 YEARS

Answer 2

I already did it 15min earlier