Arun walks ⅓ km from a place A towards east and then from there 1⅔ km towards west. Where
will he be now from A.
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Answer:
Let us denote the distance travelled towards east by positive sign so thus distance of Satypal from the point P would be
3
2
+ (−1
7
5
) =
3
2
+
7
−12
=
3×7
2×7
+
7×3
(−12)×3
=
21
14−36
=
21
−22
=−1
21
1
Since it is negative it means Satypal is at a distance 1
21
1
km towards west of P
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