Question

Aryabhatta solve only
3rd number iv and v​

Answer 1

Answer:

1st is number 5

2nd is number 4

Answer 2

Step-by-step explanation:

$given \: \: std. \: \: equation - \\ \\ = > (x + a)(x + b) = {x}^{2} + (a + b)x + ab \\ \\ (3)(iv) \: compare \: - \\ \\ a = \frac{1}{3} \: \: and \: \: b = 3 \\ \\ = > (x + \frac{1}{3} )(x + 3) = {x}^{2} + \frac{4}{3} x + 1 \\ \\ (v) \: \\ \\ equation \: \: is \: \: ( {x}^{2} + 4)( {x}^{2} + 9) \\ \\ = > put \: \: {x}^{2} = t \\ \\ now \: \: equatio n \: \: is \: = > (t + 4)(t + 9) \\ \\ compare - \\ \\ = > a = 4 \: \: and \: \: b = 9 \\ \\ then \: \: using \: \: identity- \\ \\ (t + 4)(t + 9) = {t}^{2} + 13t + 36 \\ \\ now \: \: put \: \: t = {x}^{2} ... \\ \\ = > ({x}^{2} + 4)( {x}^{2} + 9) = {x}^{4} + 13 {x}^{2} + 36$

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