As a publicity stunt Rekha sold 10 pens at a loss of 5%. Next day she raised the SP by 25% and sold 100 pens. To her dismay she found that she had gained only rupees 25 on these pens. Find the CP of these 100 pens.
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1
Answer :D
CP Of 10 Pens = 10x
SP Of 10 Pens = (10x-5 ÷ 100) × 10x = 10x-x ÷ 2 = 19x/2
SP Next Day = 19x/2+25/100*19x/2 = 19x/2+19x/8 = 95x/8
SP Of 100 Pens Next Day = 95x/8*100 = 2375x/2
Now According To The Condition Given That She Gained Only Rs 25 On These Pens
CP Of 100 Pens = 100x
2375x/2-100x = 25
2175x/2 = 25
2175x = 50
x = 50/2175
CP Of 100 Pens
50/2175*100 = Rs 2.29 Or 2.3
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Let the buying cost of each pen be x.
Given:-
Total amount received after selling is 625.
5 pens sold at 25% profit. I.e. total selling amount of each pen is (x+x/4)
5 pens sold at 50/3% loss, i.e. total selling amount of each pen is (x-x/6).
From above points 1,2 & 3.
625 = 5(x+x/4) + 5(x-x/6) = 10x + 5(x/4-x/6)
625 = 10x + 5x/12
625*12 = 125x
5*12 = x.
√ Therefore price of each pen is 60.
Verify.
From point-2, selling price of each pen(with profit) is
(x+x/4) = 60+60/4 = 75.
Therefore selling price of 5 pens with profit is 75*5 = 375.
2. From point-3, selling price of each pen(with loss) is
(x-x/6) = 60–60/6 = 50.
Therefore selling price of 5 pens at loss is 5*50 = 250.
Hence total selling price is 375+250 = 625.
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