Question

If 3tanA=4 , then find Sin A and Cos A?​

Answer 1

Solution :-

3tanA = 4

tanA = 4/ 3

As we know that,

Tan Φ = Perpendicular / base

Here,

Perpendicular = 4cm

Base = 3 cm

Let us consider the triangle ABC,

By using Pythagoras theorem,

H^2 = ( P )^2 + ( B )^2

(AC )^2 = ( 4 )^2 + ( 3 )^2

( AC )^2 = 16 + 9

( AC )^2 = 25

AC = 5

Now,

As we know that,

Sin Φ = Perpendicular / Hypotenuse

Therefore,

Sin A = 4 / 5

As we know that,

Tan Φ = Base / Hypotenuse

Tan Φ = 3 / 5

Hence, The value of Sin A = 4/5 and Tan A = 3/5$.$

Answer 2

Answer:

$\huge \underline \mathfrak \red{❁Solution❁}$

3tanA = 4

tanA = 4/ 3

As we know that,

Tan Φ = Perpendicular / base

Here,

Perpendicular = 4cm

Base = 3 cm

Let us consider the triangle ABC,

By using Pythagoras theorem,

H^2 = ( P )^2 + ( B )^2

(AC )^2 = ( 4 )^2 + ( 3 )^2

( AC )^2 = 16 + 9

( AC )^2 = 25

AC = 5

Now,

As we know that,

Sin Φ = Perpendicular / Hypotenuse

Therefore,

Sin A = 4 / 5

As we know that,

Tan Φ = Base / Hypotenuse

Tan Φ = 3 / 5

Hence, The value of Sin A = 4/5 and Tan A = 3/5