Question

As a result of change in the magnetic flux linked to the closed loop shown in the figure, an e.m.f. V volt is induced in the loop. The work done (in joule) in taking a charge Q coulomb once along the loop is
(a) QV
(b) 2QV
(c) QV/2
(d) zero

Answer 1

Answer:

A) QV

Explanation:

Work done in taking a charge = Q (Given)

Volt induced in the loop = V (Given)

Work done in moving a test charge is equal to Q around a loop that has an induced emf ∈ making it Q∈.Therefore, as the induced electric field due to change in magnetic field is non-conservative the work done due to a charge will become W = QV

Hence, The work done (in joule) in taking a charge Q coulomb once along the loop is QV

Answer 2

Answer:

Work done due to a charge W = QV

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