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inematic Equations for Uniformly Accelerated.
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25. A particle starts moving with acceleration 2 m/s2.
Distance travelled by it in 5th half second is
(1) 1.25 m
(2) 2.25 m
(3) 6.25 m
(4) 30.25 m
how tell it
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Answered by
9
Distance travelled in 5th half second = Distance travelled in 2.5 seconds - Distance travelled in 2 seconds
= 0.5a (t₁² - t₂²)
= 0.5 * 2 * (2.5² - 2²)
= 2.25m
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3
Answer:
THE ANSWER IS 2.25 M GOPE THIS HELPS YOU IN BETTER WAY PLS MARK ME AS BRAINALIST
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