Question

As object of mass m and velocity is has kinetic energy 200 joule. find the new kinetic energy if the mass of object becomes double and velocity remain same ? give step by step answer​

Answer 1

$\large \dag$ Question :-

An object of mass m and velocity v has kinetic energy 200 joule. Find the new kinetic energy if the mass of object becomes double and velocity remain same ?

$\large \dag$ Answer :-

$\red\dashrightarrow\underline{\underline{\sf  \green{New   \:  KE \:  is \: 400\: Joule }} }$

$\large \dag$ Step by step Explanation :-

Here we have,

• Mass of object = m

• Velocity of object = v

• Kinetic Energy of object = KE = 200 J

❒ We Know that Kinetic energy of any object with mass n and velocity v is given by :-

$\large \bf \red\bigstar \: \: \orange{ \underbrace{ \underline{   \blue{ \pmb {\frak{  \text{ KE}= \frac{1}{2} {m \text v}^{2} }}}}}}$

So, for given conditions ;

⏩ Applying formulaof kinetic energy ;

$:\longmapsto \rm 200 = \frac{1}{2} {mv}^{2}$

$:\longmapsto \rm mv {}^{2} = 200 \times 2$

$\purple{ \large :\longmapsto  \underline {\boxed{{\bf  {mv}^{2} = 400} }}}$

$\large \bigstar$ When Mass becomes double :-

We Have,

• Mass of object = m' = 2m

• Velocity of object = v

• Let Kinetic Energy of object = KE'

⏩ Applying formula of kinetic energy ;

$:\longmapsto \rm KE' = \frac{1}{2} m'v {}^{2}$

$:\longmapsto \rm KE' = \frac{1}{\cancel2} \times \cancel2m {v}^{2}$

$:\longmapsto \rm KE' = {mv}^{2}$

$\maltese$ Putting Value of $\sf mv {}^{2}$

$\purple{ \large :\longmapsto  \underline {\boxed{{\bf KE' = 400 \:J } }}}$

Therefore,

$\underline{\pink{\underline{\frak{\pmb{\text New \: Kinetic \: Energ \text y = 400 \:Joule }}}}}$

Answer 2

QUESTION-:

As object of mass m and velocity is has kinetic energy 200 joule. find the new kinetic energy if the mass of object becomes double and velocity remain same

EXPLANATION-:

Let the previous kinetic energy=k₁

The value of k₁

$\longrightarrow \boxed{\bf\;K.E=\frac{1}{2}mv^2}$

Finding value of k₁

$\rightarrow \bf\; 200=\frac{1}{2}mv^2\\\\\rightarrow \bf\;mv^2=400$

Now in the new kinetic energy-:

Let new K.E=k₂

mass=2m

velocity=v

Finding k2-;

$\rightarrow \bf\; k_2=\frac{1}{2}2mv^2\\\\\rightarrow \bf\; k_2=mv^2\\\\\rightarrow \bf\;k_2=400\;joules\;\;\;\;[mv^2=400]$

So new kinetic energy is 400 joules

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