As observed from the top of a 75 m high lighthouse from the sea-level, the angles of depression of two ships are 30° and 45°. If one ship is exactly behind the other on the same side of the lighthouse, find the distance between the two ships.
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Question:
As observed from the top of a 75 m high lighthouse from the sea-level, the angles of depression of two ships are 30° and 45°. If one ship is exactly behind the other on the same side of the lighthouse, find the distance between the two ships.
Answer:
75(√3-1)m
Step-by-step explanation:
Let AB be the lighthouse of height 75 m. Let C and D be the positions of the ships. 30° and 45° are the angles of depression from the lighthouse.
A/q,
In right triangle ABC,
tan 45° = AB/BC
1= 75/BC
BC = 75 m
also,
In right triangle ABD,
tan 30° = AB/BD
1/v3 = 75/BD
BD = 7573 m
The distance between the two ships = CD
= BD - BC
= (75√3 - 75) m
= 75(√3-1) m
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