Math, asked by Anonymous, 6 months ago

As observed from the top of a 75 m high lighthouse from the sea-level, the angles of depression of two ships are 30° and 45°. If one ship is exactly behind the other on the same side of the lighthouse, find the distance between the two ships.
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Answers

Answered by Anonymous
2

Question:

As observed from the top of a 75 m high lighthouse from the sea-level, the angles of depression of two ships are 30° and 45°. If one ship is exactly behind the other on the same side of the lighthouse, find the distance between the two ships.

Answer:

75(√3-1)m

Step-by-step explanation:

Let AB be the lighthouse of height 75 m. Let C and D be the positions of the ships. 30° and 45° are the angles of depression from the lighthouse.

A/q,

In right triangle ABC,

tan 45° = AB/BC

1= 75/BC

BC = 75 m

also,

In right triangle ABD,

tan 30° = AB/BD

1/v3 = 75/BD

BD = 7573 m

The distance between the two ships = CD

= BD - BC

= (75√3 - 75) m

= 75(√3-1) m

Attachments:
Answered by Qazwsx1234
1

Answer:

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