Question

As observed from the top of a light house 100m high above sea level, the angle of depression of ship, sailing directly towards it, cgsnges 30 °to 45°. Determine the distance travelled by the ship furing the period of observations...

Answer 1

Answer:

hey,

height = AB= 100

BC= x

CD=y

triangle ABC

tan60= AB/BC

√3= 100/x

x= 100/√3

In triangle ABD

tan30= AB/CD

1/√3= 100/y

y= 100√3

as we know

BD=BC+ CD

y= x+ CD

CD= y-x

putting the values we get

CD= 100 x (3-1) /√3

=100 x 2/√3

=200/√3

thanks.......... ^^