As observed from the top of a light house 100m high above sea level, the angle of depression of ship, sailing directly towards it, cgsnges 30 °to 45°. Determine the distance travelled by the ship furing the period of observations...
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Answer:
hey,
height = AB= 100
BC= x
CD=y
triangle ABC
tan60= AB/BC
√3= 100/x
x= 100/√3
In triangle ABD
tan30= AB/CD
1/√3= 100/y
y= 100√3
as we know
BD=BC+ CD
y= x+ CD
CD= y-x
putting the values we get
CD= 100 x (3-1) /√3
=100 x 2/√3
=200/√3
thanks.......... ^^
shazia999:
kaise h
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