Question

As observed from the top of light house 100m tall the angle of depression of two ships are 30 and 45. Find the distance between the ships

Answer 1

the given observed observes two ship at angle of depression ACB 30 and ADB 45 from light house of tall AB =100m

apply tan at ACB
tan∆=0pp/adj
tan 45=100/BC
1=100/BC
therefore BC=100m

apply tan at ADC
tan∆=opp/adj
tan35=100/BD
o.5773=100/BD
BD=57.73m

distance between two ships is 100-57.73=42.27m