Question

As observed from the top of the seventy five meter high light house from the sea level the angle of depression of the two ships are 30 and 45 .If one ship is extra behind the of others on the same side of the lighthouse find the distance between the two ships

Answer 1

Answer:

Step-by-step explanation:

Let AB be the h of the light house

AB=h=75

C be the first ship

D be the second ship

Let distance between 1st ship and light house be x and 2nd ship and lighthouse be y

Tan theta =opp/ hyp

Tan 30°=1/root3

Therefore,

x/75=1/root3

This implies x=25root3

Similarly we find y=75

The distance between the ships is

DB-CB

=75-25root3

=25(3- root3)

=25root3(root3-1)

This is the solution i found