As part of a collage for her art class, Sheila wants to enclose a
rectangle with 100 inches of yarn. Write an expression for the area
A of the rectangle in terms of w (width).
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let the length of rectangle be L
let the breadth of rectangle be B
area of rectangle = L X B --------------------- (1)
PERIMETER OF RECTANGLE = 2(L+B) = 100
2L + 2B = 100
L+B =50
L=50-B------------------- (2)
SUBSTITUTE 2 IN 1
A= (50-B) X B
A = 50B - B²
let the breadth of rectangle be B
area of rectangle = L X B --------------------- (1)
PERIMETER OF RECTANGLE = 2(L+B) = 100
2L + 2B = 100
L+B =50
L=50-B------------------- (2)
SUBSTITUTE 2 IN 1
A= (50-B) X B
A = 50B - B²
Answered by
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Let the length of the rectangle = l
width of the rectangle = w
we know that ,
Area = l *w
⇒ Area = l × w............(1)
2l + 2w = 100
⇒2( l + w) = 100
⇒ (l+w) = 100/2 = 50.
⇒ l = 50 - w...........(2)
Now , substitute (2) in (1).
⇒ A = (50 - w) × w
⇒ A = 50w - w²
Area = 50w - w².
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