Question

As per this diagram a point charge +q is placed at the origin O. Work done in taking another point charge – Q from the point A [coordinates (0, a)] to another point B [coordinates (a, 0)] along the straight path AB is
(a) zero
(b) $\bigg \lgroup \frac{-qQ}{4\pi\epsilon_{0}}\frac{1}{a^{2}}\bigg \rgroup \sqrt{2}a$(c) $\bigg \lgroup \frac{qQ}{4\pi\epsilon_{0}}\frac{1}{a^{2}}]\bigg \rgroup \frac{a}{\sqrt{2}}$(d) $\bigg \lgroup \frac{qQ}{4\pi\epsilon_{0}}\frac{1}{a^{2}}\bigg \rgroup \sqrt{2}a$

Answer 1

Hey

at the origin O. Work done in taking another point charge – Q from the point A [coordinates

D correct

Answer 2

Explanation:

D is the right answer .....