Question

As shown in figure force F = 100 N is applied horizontally on a block of mass 4 kg. Which is in contact with a wall. Such that it does not fall. The coefficient of friction between the block and the wall is (g = 10 ms–2) A 0.4 B 0.5 C 0.3 D 0.8As shown in figure force F = 100 N is applied horizontally on a block of mass 4 kg. Which is in contact with a wall. Such that it does not fall. The coefficient of friction between the block and the wall is (g = 10 ms–2) A 0.4 B 0.5 C 0.3 D 0.8

Answer 1

Answer:

Static friction is a self-adjusting force.

The limiting value of friction up to which the body stays at rest till it starts moving is given by, F  

s

​  

=μmg

where μ is the coefficient of static friction.

Below that limit, the frictional force is equal to the force applied.

Here F  

s

​  

=0.8×4×10=32N ;   g=10m/s  

2

 

Whereas force applied is 19N less than the limiting value of friction.

Hence Frictional force is 19N.  

Explanation: