असमिका 4x+3<5x+7 को हल किजिए जबकि x एक वास्तविक संख्या है
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Given : असमिका 4x+3<5x+7 x एक वास्तविक संख्या है
Inequality 4x+3<5x+7 , x ∈ R
To Find : हल किजिए
Solve
Solution:
4x+3 < 5x + 7
Subtract 4x from both sides
=> 4x + 3 - 4x < 5x + 7 - 4x
=> 3 < x + 7
Subtract 7 from both sides
=> 3 - 7 < x + 7 - 7
=> - 4 < x
=> x > - 4
x ∈ ( - 4 , ∞ )
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