Asha and reema can weave a certain number of baskets in 25 days and 30 days respectively. They work together for 5 days and then asha leaves. In how many days will reema finish the rest of the work.
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Answered by
9
In 1 day Asha can weave 1/25 of the baskets
In 1 day Reema can weave 1/30 of the baskets
∴ (Reema and Asha)'s 1 day work = (1/30) + (1/25) = 11/150
∴ (Reema and Asha)'s 5 days work = (11/150) x 5 = 11/30 Work left = 1 - (11/30) = 19/30= 11/30
∴ No. of days taken by Reema to finish the remaining work = (19/30) ÷ (1/30)
= 19 days
In 1 day Reema can weave 1/30 of the baskets
∴ (Reema and Asha)'s 1 day work = (1/30) + (1/25) = 11/150
∴ (Reema and Asha)'s 5 days work = (11/150) x 5 = 11/30 Work left = 1 - (11/30) = 19/30= 11/30
∴ No. of days taken by Reema to finish the remaining work = (19/30) ÷ (1/30)
= 19 days
reishumwi:
Hope it helps u.... :-)
Answered by
3
Productivity of Asha = 1/25 of total work per day.
In 5 days she did 1/5 of work
Productivity of Reema = 1/30 of total work per day.
in 5 days she did 1/6 of total work
In 5 days they did : 1/5 + 1/6 = 11/30 of total work
Work remaining = 1 - 11/30 = 19/30 unit
Reema will take : work to do / productivity per day
= (19/30) / (1/30)
= 19 days to complete the work.
In 5 days she did 1/5 of work
Productivity of Reema = 1/30 of total work per day.
in 5 days she did 1/6 of total work
In 5 days they did : 1/5 + 1/6 = 11/30 of total work
Work remaining = 1 - 11/30 = 19/30 unit
Reema will take : work to do / productivity per day
= (19/30) / (1/30)
= 19 days to complete the work.
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