Ashish purchased a boat for rupees 16000. if after 2 years the price of the boat became 14440. find the rate of depreciation.
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Cost price of the scooter(c) = Rs16000
Let the Rate of depreciation = d %
scooter price after 2 years
S = Rs 14440
S = c ×(100 - d )/100× (100-d)/100
14440 = 16000 × (100 - d )^2 /10000
( 14440 × 10000)/16000 = ( 100 - d )^2
( 144400/16) = ( 100 - d )^2
9025 = ( 100 - d )^2
95 = 100 - d
d = 100 - 95
d = 5 %
Rate of the depreciation = d = 5 %
I hope this helps you.
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