Question

Ashok brought a second hand car for rupees 90,000 he paid 1 by 6 of the price in cash and the rest in 10 equal monthly installment find the amount he had to pay every month​

Answer 1

Step-by-step explanation:

Cost of the second hand car= 90000 rupees.

Fraction of money he paid in cash=1/6

Therefore,total money he paid in cash=

90000×1/6=15000

Now,the money left=

90000-15000=75000

Money he paid in 10 equal month=

75000/10=7500

I think it's right

hope it helps you ....

Answer 2

Answer:

The amount 7500 rupees he had to pay every month.

Step-by-step explanation:

Given,Ashok brought a second hand car for rupees 90,000.

So,cost price of the car is 90000 rupees.

It is also given that he paid 1 by 6 of the price in cash .

So,he paid in cash $= \frac{1}{6} \: of \: total \: amount$

Here total amount $= 90000 \: rupees$

Therefore he paid in cash

$= \frac{1}{6} \times 90000 \\ = \frac{90000}{6} \\ = 15000 \: rupees$

Again given that the rest paid in 10 equal monthly installment.

Rest of money

$= (90000 - 15000) \\ = 75000 \: rupees$

According to question,

75000 is paid by 10 equal monthly installment.

So,he paid in 10 months 75000 rupees.

By Unitary method,he paid in 1 month

$\frac{75000}{10} \\ = 7500 \: rupees$

Know more about Unitary method,

https://brainly.in/question/861311

https://brainly.in/question/861580

#SPJ2