Math, asked by SatvikVats1531, 11 months ago

Ashu is x years old while his mother Mrs. Veena is x² years old. Five years hence Mrs. Veena will be three times old as Ashu. Find their present ages.

Answers

Answered by darkscropoin8847
0

Answer:

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Answered by dheerajk1912
0

Ashu is 5 years Mrs. Veena is 25 years old.

Step-by-step explanation:

  • Given data

        Present age of Ashu = X years

        Present age of Mrs. Veena \mathbf{=X^{2} \ years}

        After 5 years will be

        Ashu age  = X +5

        Mrs. Veena \mathbf{=X^{2} +5 \ years}

  • It is given that

        Mrs. Veena age will be three times Ashu age

        \mathbf{X^{2} +5= 3(X+5)}

        \mathbf{X^{2}+5= 3X +15}

        \mathbf{X^{2}-3X -15+5= 0}

        \mathbf{X^{2}-3X -10= 0}        

  • Above equation can be solved by middle term splitting method

        \mathbf{X^{2}-5X+2X-10= 0}

        \mathbf{X(X-5) +2(X-5)= 0}

        \mathbf{(X-5)(X+2)= 0}

  • So product is zero only when

        X-5= 0            or    X+2 =0

        X = 5              or   X = -2    (This is not acceptable)

        So value of X = 5

  • Means

       Present age of Ashu = X = 5 years

       Present age of Mrs. Veena \mathbf{=X^{2} =5^{2}=25 \ years}

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