Math, asked by mimi7328, 1 year ago

Ashu is x years old while his mother mrs veena is x2 years old.5 years hence, mrs. veena will be three times old as ashu. find their present ages.

Answers

Answered by rahul12742
0
ashu is x years old
her mother veena is 2x years old
Acc. to question
3(x+5)=2x+5
3x+15=2x+5
3x-2x=15-5
x=10
Answered by chopraneetu
0
let the present age of Sonu be x year
mrs Veena's age be x^2 year
5 years hence
Ashu's age=x+5 year
veena \: age \: = {x}^{2} + 5 \: year \\
ATQ

3(x + 5) = {x}^{2} + 5 \\ 3x + 15 = {x}^{2} + 5 \\ {x}^{2} - 3x - 10 = 0 \\ {x}^{2} - 5x + 2x - 10 = 0 \\ x(x - 5) + 2(x - 5) = 0 \\ ( x- 5)(x + 2) = 0 \\ x = 5 \: or \: - 2 \\
Age can't be negative so x= 5
Ashu's present age is 5 year
Veena's age=5×5=25 year
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