Question

A sand bag of 10kg is suspended by a 3m string weigh less string. a 0.2kg mass bullet enters the bag with a velocity of 20m/s. and get embedded into it. the loss of kinetic energy in collision is

Answer 1

mass of bag, m1=mmass of bullet, m2=m20velocity of bag, v1=0velocity of bullet, v2=vAccording to law of conservation of linear momentum,m×0+m20×v=(m+m20)Vwhere, V=final velocity of bag and bullet embedded in it.m20×v=(21m20)VV=mv20×2021m=v21