Question

Ashwin walks 10m north,12m east, 3m west and 5m south and then stops to drink water. What is the magnitude of displacement from his original point

Answer 1

Answer:

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Answer 2

Answer:

Step-by-step explanation:

Given that ,

Ashwin walks 10m north,12m east, 3m west and 5m south and then stops to drink water. What is the magnitude of displacement from his original point.

As per question ,

Ashwin walked 10 m north.

then turn 12 m east and again turn 3 m west on the same path,

it means it travelled (12-3)m = 9m east.

And again 5 m south direction.

So, the displacement of the Ashwin from initial position to final position

is,

      = $\sqrt{(5)^{2}+(9)^{2} }$

      = $\sqrt{25 + 81}$

      = $\sqrt{106}$ m

Therefore , the displacement from initial position to final position of Ashwin is $\sqrt{106}$ m.

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