asin ^3x + bcos^3x = sinxcosx
Then find a^2 + b^2 when asinx = bcosx
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Step-by-step explanation:
asin^3x+asinx×cos^2x =sinxcosx
asinx (sin^2x +cos^2x)=sinxcosx
asinx=sinxcosx
a=cosx
b=sinx( because asinx =bcosx)
a^2+b^2=sin^2x+cos^2x
=1
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