Math, asked by bhaskararaomatcha197, 10 months ago

asin ^3x + bcos^3x = sinxcosx
Then find a^2 + b^2 when asinx = bcosx

Answers

Answered by jagadeeshreddy31

5

Step-by-step explanation:

asin^3x+asinx×cos^2x =sinxcosx

asinx (sin^2x +cos^2x)=sinxcosx

asinx=sinxcosx

a=cosx

b=sinx( because asinx =bcosx)

a^2+b^2=sin^2x+cos^2x

=1

if it helps mark me as brainliest

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