Question

Asin theta = Bcos theta then the value of secant square theta will be.

Answer 1

Answer:

secant square theta = 1 + B^2/A^2

Step-by-step explanation:

A sin theta = B cos theta

A/B = cos theta / sin theta

A/B = cot theta

tan theta = B/A

Sec^2 theta - tan^2 theta = 1

sec^2 theta = 1 + (B/A)^2

Sec^2 theta = 1+ B^2/A^2

Answer 2

Answer:

\frac{A^{2} +B^{2} }{A^{2} }

I HAVE USED P INSTEAD OF THETA

Step-by-step explanation:

$\frac{sin p}{cos p} =\frac{B}{A}\\ tan p=\frac{B}{A}\\ tan^{2}p=\frac{B^{2} }{A^{2} }  \\sec^{2} p-1=\frac{B^{2} }{A^{2} }\\sec^{2} p=1+\frac{B^{2} }{A^{2} }=\frac{A^{2} +B^{2} }{A^{2} }$