Question

asin² Ф +bcos ² Ф=c then tan²Ф =

Answer 1

Answer:

asin2θ+bcos2 θ=c

cos^2θ(atan2 θ+b)=c

atan^2 θ+b=csec^2 θ

atan^2θ+b=c+ctan^2 θ

(a−c)tan^2 θ=c−b

∴tan^2 θ= c−b /  a−c

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