Ask your question a ping pong ball has a volume v and density 1/7th that of liquid. what force would be required to hold it completely inside the liquid.here
kvnmurty:
if a user writes wrong or crazy answer, u r supposed to click on "Ask our moderators to review it " blue link.
Answers
Answered by
55
Ping pong ball density relative to the liquid = 1/7
volume of ball = V
let the density of liquid be = d
acceleration due to gravity = g
The apparent weight of the ball = weight - buoyancy force
= (V d/7 ) g - (V d) g = - (6 Vdg) / 7
The apparent weight the force upwards. So to push it inside the water and hold it inside water a force of 6 Vdg/7 is required.
volume of ball = V
let the density of liquid be = d
acceleration due to gravity = g
The apparent weight of the ball = weight - buoyancy force
= (V d/7 ) g - (V d) g = - (6 Vdg) / 7
The apparent weight the force upwards. So to push it inside the water and hold it inside water a force of 6 Vdg/7 is required.
Answered by
7
Answer:
6vg/7
Explanation:
The force requires to hold it completely inside the liquid is the apparent weight.
Apparent weight= weight of body - buoyant force
= vg-(vg/7)
=6vg/7
Similar questions