Asla consists of two parallel layers of copper and brass of same thickness and having thermal conductivities in the ratio 1 by 4 is free surface of brass is at hundred degree celsius and that of corporate zero degree celsius the temperature of interfaces
Answers
Answered by
2
Hey mate!!!!!
Here is your answer... .
The amount of heat flowing per second is :
dQ/dt = KA.dT/L
K1:K2 = 1:4
let temp. of junction is T , as heal flow rate is same
K1.(100-T) = K2.(T-0)
temp of junction is 20 C
hope it helps. ...
plz mark it as brainiest.....
Similar questions