Question

Aslam has56 bowl with 7 fishes in each bowl s how many fishes are there?​

Answer 1

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$\small \red{Given}$

$\small\red{{First \: diagonal \: of \: the \: rhombus \: = 20 m}}$

$\small \red{{ second \: of \: the \: rhombus = \: 40 m}}$

$\small\red{{We \: know \: that ,}}$

$\small \red{Area \: of \: a \: rhombus = \: \frac{1}{2} \times d(1) \times d(2)}$

$\small \red{{\tt \implies \: \frac{1}{2} \times 20 \times 40 }}$

$\small \red{{ \tt \implies \: \frac{1}{2} \times 800 }}$

$\small \red{{\tt \implies \frac{1}{2} \times 800 = 400 \: m^{2} }}$

$\small \red{{And \: also \: given \: that ,}}$

$\small \red{{Area \: of \: the \: rhombus \: = Area \: of \: square}}$

$\small \red{{We \: know \: that \: , area \: of \: a \: square = (Side)^{2} }}$

$\small \red{{Hence , \: 400 \: m^{2} = (side)^{2} }}$

$\small \red{{ \tt \implies \:(20)^{2} =(side)^{2} }}$

$\small\red{{ \tt \implies \:side = \sqrt{(20)^{2} }}}$

$\small \red{{\tt\implies \:Side = 20 \: m}}$

$\small \red{{We \: know \: that , \: Perimeter \: of \: a \: square = \: 4 \times Side}}$

$\small \red{{\tt \implies \: 4 \times 20 \: m}}$

$\small \red{{ \tt \implies \: 80 \: m}}$

$\small \red{{Hence \: , Perimeter \: of \: a \: square \: = 80 m }}$

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Answer 2

Answer:

Aslam has 56 bowls

fishes in each bowl =56/7

=8 ....

....hope it helps u