Question

Assem went to a stationery shop and purchased 3 pens and 5 pencils for rupees 40 this cousin manik bought 4 pencils and 5 pens for rupees 58. if cost of 1 penis rupees X and 1 pencil is y then which of the following represent the situation algebraically.

Answer 1

Given, cost of pen = x
            cost of pencil = y
The equation for the first case is 
      3x + 5y = 40
The equation for the second case is
      5x + 4y = 58
Let's multiply the equation for the first case with 5. Then we get,
     15x + 25y = 200                           -- Equation 1
Let's multiply the equation for the second case with 3. Then we get,
     15x + 12y = 174                           -- Equation 2
Let us solve Equation 1 and Equation 2,
                                15x + 25y = 200
                             -  15x + 12y = 174
                        ------------------------------------
                                           13y = 26
                                              y = 2
Substituting the 'y' value in the equation for the first case, we get
                                      3x + 5(2) = 40
                                       3x + 10 = 40
                                          3x = 30
                                           x = 10 
Hence, the cost of pen = 10 rupees
             the cost of pencil = 2 rupees

Hope my answer helps me.. 

Answer 2

Step-by-step explanation:

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