Assertion (A): If (x - 1) is a common factor of f(x) and g(x), then f(1) = g(1).
Reason (R) : The common factor of f(x) and g(x) is their HCF.
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Step-by-step explanation:
1) If (x - 1) is a common factor of f(x) and g(x), then
f(1) = g(1).
By factor theorem
If (x-1) is a factor then by factor theorem f(1)=0---(1)
and similarly , g(1)=0----(2)
since x-1 is a common factor of f(x) and g(x)
=>f(1)=g(1)
2) The common factor of f(x) and g(x) is their HCF.
Let (x-a) is a factor of f(x) then
f(x)=(x-a)q1(x).....(1)
and g(x)=(x-a)q2(x)---(2)
From (1)&(2)
Common factor (x-a)
it is the heighest Common factor
so HCF=x-a
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