Assign a variable and write an equation for the situation below. Then solve the equation.
1. Find three consecutive integers whose sum is 48.
2. Find three consecutive odd integers whose sum is -465.
please answer the two questions. :)
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Hey... Here is the answer for 1st one
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yassinsobh200:
could you please answer this for me ?
f) The sum of three integers is 228. The second integer is 1 more than the first, and the third integer is 2 more than the fist. Write an equation to determine the integers. Solve your equation.
Answered by
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1. x+x+1+x+2 = 48
3x+3 = 48
3x = 48-3
3x= 45
x= 45/3
x= 15
hence numbers are 15,16,17
2.x+x+2+x+4 = -465
3x+ 6 = -465
3x = -465 -6
3x = -471
x = -471/3
-157
hence numbers are -157, -155,-153
3x+3 = 48
3x = 48-3
3x= 45
x= 45/3
x= 15
hence numbers are 15,16,17
2.x+x+2+x+4 = -465
3x+ 6 = -465
3x = -465 -6
3x = -471
x = -471/3
-157
hence numbers are -157, -155,-153
The sum of three integers is 228. The second integer is 1 more than the first, and the third integer is 2 more than the fist. Write an equation to determine the integers. Solve your equation.
could you please answer this for me ?
I can
x+x+1+x+2 = 228........3x+3 = 228........3x=228-3 ........3x= 225 .....x= 225/3......x = 75....numbers are 75,76,77
Let the first integer be x.... Then the second integer will be x+1 and the third would be x+2......Now x+x+1+x+2=228...3x+3=228
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