Question

assign hybridization of each of carbon atoms and write total​ number of bonds as well as specify sigms

Answer 1

Answer:

Start by drawing the Lewis structure of acetonitrile,

CH

3

CN

.

The total number of valence electrons present in a molecule of acetonitrile will be equal to

16

because you have

2

×

4 e

−

=

8 e

−

→

from two atoms of carbon,

C

3

×

1 e

−

=

3 e

−

→

from three atoms of hydrogen,

H

1

×

5 e

−

=

5 e

−

→

from one atom of nitrogen,

N

Now, the two carbon atoms will be bonded together via a single bond. One of the two carbon atoms will be bonded to the nitrogen atom via a triple bond and the other will be bonded to the three hydrogen atoms via single bonds.

This will account for

4

×

2 e

−

+

1

×

6 e

−

=

14 e