Question

assign oxidiation numbers to the underline elements each of the following species (a) k2Mno4 (b)H2S2O7
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Answer 1

(a) KMnO4

In KMnO4, the oxidation number of Mn can be found out by taking it as x

ON of K = +1

ON of O = -2

Since, KMnO4 is stable,

1+x-8 = 0 ------> x = +7

(b) H2S2O7

In H2S2O7, the oxidation number of S can be found out by taking it as x

ON of H = +1

ON of O = -2

Since H2S2O7 is stable,

2+2x-14 = 0 --------> 2x = 12 ------> x = +6

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