Question

assign the position of the elements having outer electronic configuration (n-2) F2 ( n-1)D2 ns2 for n=6​

Answer 1

Explanation:

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Answer 2

Answer:

Explanation:(i) For n=3, the period in which the element belongs is third. The electronic configuration is 3s  

2

3p  

4

  and the element belongs to p block. The group number of the element is 10+ number of electrons in the valence shell.

=10+6=16

Thus, the element belongs to third period and sixteenth group.

(ii) For n=4, the period in which the element belongs is fourth. The electronic configuration is 3d  

2

4s  

2

 and the element belongs to d block. The group number of the element is = number of electrons in the (n−1)d subshell + number of electrons in ns subshell=2+2=4

Thus, the element belongs to fourth period and fourth group.

(iii) For n=6, the period in which the element belongs is sixth. The electronic configuration is 4f  

7

5d  

1

6s  

2

  and the element belongs to f block.  All f block elements belong to third group.

Thus, the element belongs to sixth period and third group.

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