Question

Assume pupil diameter to be 2.5 mm assume light of wavelength 500 nm what is the minimum distance between two point object that can be seen clearly by the eye when kept at least distance of distinct vision

Answer 1

Answer:

Heyy..

The answer is 25 cm.

hope it helps...❤..

Answer 2

Given that,

The diameter of the pupil of an eye, D = 2.5 mm

The wavelength of the light, $\lambda=500\ nm=5\times 10^{-7}\ m$

To find,

The minimum distance between two point object that can be seen clearly by the eye when kept at least distance of distinct vision.

Solution,

Let d is the minimum distance. So, using the formula as follows we get :

$\sin\theta=\dfrac{1.22\lambda}{D}\\\\\dfrac{d}{L}=\dfrac{1.22\lambda}{D}\\\\d=\dfrac{1.22\times\lambda\times L}{D}$

L is the viewing distance. For the least distance of distinct vision it is equal to 25 cm.

Putting all the values in above formula we get :

$d=\dfrac{1.22\times\lambda\times L}{D}\\\\d=\dfrac{1.22\times5\times 10^{-7}\times 0.25}{2.5\times 10^{-3}}\\\\d=6.1\times 10^{-5}\ m$

So, the minimum distance between two points is $6.1\times 10^{-5}\ m$.