Question

Assume that 20 cows and 40 goats can be kept for 10days for Rs.460. If the cost of keeping 5 goats is thesame as the cost of keeping 1 cow, what will be the
cost for keeping 50 cows and 30 goats for 12 days?

A. Rs.1104
B. Rs.1000
C. Rs. 934
D. Rs. 1210​

Answer 1

Answer:

$\boxed{\sf Cost\; of\; keeping\; 50\; cows \;and \;30 \;goats\; for\; 12 \;days\; is\; Rs.1104}$

Step-by-step explanation:

Let us assume that cost of keeping a cow for 1 day is Rs x

and the cost of keeping a goat for one be y

∵ It is given that cost of keeping 20 cows and 40 goats can be kept for 10 days for Rs.460.

The cost of keeping 20 cows and 40 goats for one day = Rs 460/10 = Rs 46.

∴ From the question,

20x + 40 y = 46

Diving throughout by 2,

$\implies$ 10x + 20y = 23 $\longrightarrow$ (1)

It is also given in the question that cost of keeping a cow is the same as keeping 5 goats.

i.e, 5y = x

On substituting this relation in(1),

10x+4x = 23

$\implies$ 14x = 23

So, x = 23/14

∴ The cost of keeping 50 cows and 30 goats for 1 day will be

Cost = 50x + 30y

On substituting , 5y = x

Cost = 50x + 6x

Cost = 56 x

On substituting , x = 23/14

Cost = 56×$\dfrac{23}{14}$

Cost = 4× 23 = Rs 92

∵ The cost of keeping 50 cows and 30 goats for 1 day is  Rs 92.

The cost of keeping 50 cows and 30 goats for 12 days = 12 ×92 = $\underline{\underline{{\bold Rs 1104}}}$

Answer 2

Answer:

Answer:

\boxed{\sf Cost\; of\; keeping\; 50\; cows \;and \;30 \;goats\; for\; 12 \;days\; is\; Rs.1104}Costofkeeping50cowsand30goatsfor12daysisRs.1104

Step-by-step explanation:

Let us assume that cost of keeping a cow for 1 day is Rs x

and the cost of keeping a goat for one be y

∵ It is given that cost of keeping 20 cows and 40 goats can be kept for 10 days for Rs.460.

The cost of keeping 20 cows and 40 goats for one day = Rs 460/10 = Rs 46.

∴ From the question,

20x + 40 y = 46

Diving throughout by 2,

\implies⟹ 10x + 20y = 23 \longrightarrow⟶ (1)

It is also given in the question that cost of keeping a cow is the same as keeping 5 goats.

i.e, 5y = x

On substituting this relation in(1),

10x+4x = 23

\implies⟹ 14x = 23

So, x = 23/14

∴ The cost of keeping 50 cows and 30 goats for 1 day will be

Cost = 50x + 30y

On substituting , 5y = x

Cost = 50x + 6x

Cost = 56 x

On substituting , x = 23/14

Cost = 56×\dfrac{23}{14}1423

Cost = 4× 23 = Rs 92

∵ The cost of keeping 50 cows and 30 goats for 1 day is  Rs 92.

The cost of keeping 50 cows and 30 goats for 12 days = 12 ×92 = \underline{\underline{{\bold Rs 1104}}}Rs1104

Hope it helps you.

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