Assume that an object of mass 40 kg having velocity 4 m/s collides with another object of mass 60 kg having velocity 2 m/s, the collision is perfectly inelastic. how much energy will loss?
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1
m1v1=m2v2
a.t.t,the energy lost will be 40
a.t.t,the energy lost will be 40
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4
Answer:
Step-by-step explanation:
Here m1 = 40kg , u1 = 4m/s
m2 = 60kg , u2 = 2m/s
So loss in energy ∆K =
1/2 × m1m2/m1+m2 × (u1 - u2)^2
= 1/2 × 40×60 / 40+60 × (4 - 2)^2
= 1/2 × 2400/100 × 4
= 1/2 × 24 × 4
= 48j Ans
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