Question

Assume that human body is 80% water. Calculate the number of molecules of water that are present in the body of a person whose weight is 65 kg

Answer 1

$answer \: is \: 1.739 \times {10}^{22}$

Answer 2

Answer:

So the total number of moles that present in the body of that person is  1.739 x 10 ²²

Explanation:

Determine the mass of the substance, and its molar mass. Divide the given mass via way of means of its molar mass to get moles, then multiply instances 6.022×1023molecules1mol

One mole of a substance is identical to 6.022 × 10²³ gadgets of that substance (consisting of atoms, molecules, or ions). The quantity 6.022 × 10²³ is called Avogadro's quantity or Avogadro's constant.

Here we must discover the quantity of molecules of water which might be nonetheless gift withinside the frame of that character having weight of sixty five kg.

80/one hundred x 5 = mass of water

M/Mass of Water= n/ N

52/18 x Nₐ = 26/ nine x Nₐ

= 1.739 x 10 ²²

So the whole quantity of moles that gift withinside the frame of that character is  1.739 x 10 ²²

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