Assume the value of 'x' and 'y' so that i can solve it graphically. ( 5x - 6y + 30 = 0 ; 5x + 4y - 20 = 0 )
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Given:
5x - 6y + 30 = 0
5x - 6y = -30 ---- (1)
5x + 4y - 20 = 0
5x + 4y = 20 ---- (2)
On solving (1) & (2), we get
5x - 6y = -30
5x + 4y = 20
-----------------
-10y = -50
y = 5.
Substitute y = 5 in (1), we get
5x - 6y = -30
5x - 6(5) = -30
5x - 30 = -30
5x = 0
x = 0.
Therefore the value of x = 0 and y = 5
Hope this helps!
5x - 6y + 30 = 0
5x - 6y = -30 ---- (1)
5x + 4y - 20 = 0
5x + 4y = 20 ---- (2)
On solving (1) & (2), we get
5x - 6y = -30
5x + 4y = 20
-----------------
-10y = -50
y = 5.
Substitute y = 5 in (1), we get
5x - 6y = -30
5x - 6(5) = -30
5x - 30 = -30
5x = 0
x = 0.
Therefore the value of x = 0 and y = 5
Hope this helps!
siddhartharao77:
:-)
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