Question

Assuming complete dissociation, calculate the pH of the given solution: 0.002 M KOH

Answer 1

On assuming complete dissociation, calculate the pH of the given solution:

0.002 M KOH[OH-] = 2 × 10^-3

then the pOH = -log(2 × 10^-3) so

then the pOH = 2.69 so  

then the pH = 14 - 2.69 so

pH = 11.31is the answer.

Hence the solution is solved with the equation respectively.