Question

Calculate the pH of the given solution: 2 g of TIOH dissolved in water to give 2 litre of solution.

Answer 1

For 2g of TlOH dissolved in water to give 2 L of solution:

[TIOH(aq)] = 2/2 g/L

= 2/2 x 1/221 M

= 1/221 M

TIOH(aq)  →  TI+(aq)  +  OH-(aq)

OH-(aq)  =  TIOH(aq) = 1/221M

Kw  =  [H+] [OH-]

10-14 = [H+] [1/221]

[H+] = 221x10-14

⇒ pH  =  -log [H+]  = -log ( 221x10-14)

= 11.65

hence the solution is solved respectively