Assuming rydberg constant to be 109670/cm,the longest wavelength line in the lyman series of the hydrogen spectrum is
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The longest wavelength line in the Lyman series of the hydrogen spectrum is 1215.7A˚.
This can be calculated in the following ways:
- We know that, for Lyman series, n₁ = 1
- The wavelength can be calculated by the formula -
1 / λ = R[ (1 / (n₁)²)− (1 / (n₂)²) ] x Z² where, R = Rydbergs constant (109670/cm) and Z = atomic number
- As per the question, we have to find the longest wavelength and this implies that the energy difference in two states showing transition should be minimum, i.e., n₂=2.
- Thus, 1 / λ = R [ (1 / 1²) − (1 / 2²) ]
1 / λ = 3 / 4 R
λ = 4 / 3 x 1 / R
= 1215.7A˚
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