Physics, asked by paraghq3254, 10 months ago

Assuming specific gravity of soil solids as 2.5 and dry unit weight of soil 19.62 kn/m3, the shrinkage limit (ws) is

Answers

Answered by sonuvuce
0

Assuming specific gravity of soil solids as 2.5 and dry unit weight of soil 19.62 kN/m³, the shrinkage limit (ws) is 10%

Explanation:

Note: This is a question of Civil Engineering

Given

Dry unit weight of soil

\gamma_d=19.62] kN/m³

Specific Gravity of soil solids

G=2.5

We know that

\gamma_d=\frac{G\gamma_w}{1+e}

\implies 19.62=\frac{2.5\times 9.81}{1+e}

\implies 1+e=\frac{2.5\times 9.81}{19.62}

\implies 1+e=1.25

\implies e=1.25-1=0.25

Thus Shrinkage Limit

w_s=\frac{e}{G}

\implies w_s=\frac{0.25}{2.5}

\implies w_s=10\%

Hope this answer is helpful.

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