Physics, asked by damini1531, 9 months ago

Assuming that a positive charge Q is uniformly
distributed over the surface of a shell, the field at
distance r from the centre of the shell where r = 3R
(R being the radius of the shell), is ...

Answers

Answered by RDalal
0

Answer:

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Answered by ShreyaNegi02
0

Answer:

Electric field at a distance 3R from the center of shell  carrying charge Q is       E= \frac{1}{4\pi \epsilon} \frac{Q}{9R^{2} } \\

Explanation:

The following relation gives the electric field at a distant point from the surface of a spherical shell.            

                E= \frac{1}{4\pi \epsilon} \frac{q}{r^{2} } \\

 where

q is the total charge on the sphere

r = the distance between the point on the sphere and point where the field must be calculated.

Given : a charged spherical shell  of radius R with total charge Q.               r = 3R  where electric field has to be calculated

Now

 E =\frac{1}{4\pi \epsilon} \frac{Q}{(3R)^{2} } \\\\E = \frac{1}{4\pi \epsilon} \frac{Q}{9R^{2} } \\

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