Question

Assuming that sap in trees has the same
characteristics as water and that it rises purely
purely due to capillary phenomenon, what will be the
average diameter of capillary tubes in a tree if the
sap is carried to a height of 10 m ? (Take Surface
Tension of water as 0.0735 N/m) (1 marks )
Ans.
0.003 mm
0.03 mm
0.3 mm
0.006 m
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Answer 1

Step-by-step explanation:

0.000000000000000003mmm

Answer 2

Answer:

Diameter is 0.003 mm.

Step-by-step explanation:

h = $\frac{2Scos\alpha}{rdg}$

where h is the maximum height

S is the surface tension

α is the angle between water and capillary.

r is the radius of the tube

d is the density of liquid

and, g is the gravity constant.

Here, we have to determine r.

So, 10 = $\frac{2 X 0.0735 X cos 0}{r X 10^{3} X 9.8}$

r x $10^{4}$ x 9.8 = 2 x 0.0735

r = $\frac{0.147 X 10^{-4}}{9.8}$

r = 0.015 x $10^{-4}$

r = 0.0000015 m

r = 0.00015 cm

r = 0.0015 mm

Diameter = 2r

                = 2 x 0.0015

Diameter = 0.003 mm

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